x^2-2x=4x+35

Solution for x^2-2x=4x+35 equation:

x^2-2x=4x+35

We move all terms to the left:

x^2-2x-(4x+35)=0

We get rid of parentheses

x^2-2x-4x-35=0

We add all the numbers together, and all the variables

x^2-6x-35=0

a = 1; b = -6; c = -35;
Δ = b2-4ac
Δ = -62-4·1·(-35)
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{11}}{2*1}=\frac{6-4\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{11}}{2*1}=\frac{6+4\sqrt{11}}{2}
$